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(cotx + cscx(1-cosx)= SIN x
express this in sinx
(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
1 answer
asked by
linds
1,446 views
My previous question:
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
2 answers
asked by
Jon
972 views
Verify the identity .
(cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant help you (cscX-cotX)=1/sinX - cosX/sinX = (1-cosX)/sinX If
0 answers
asked by
Rose
771 views
express in sinx
1 1 ---------- + -------- cscx + cotx cscx - cotx and express in cosx 1 + cot x ------- - sin^2x cscx = 1/sinx so
0 answers
asked by
linds
811 views
Prove the identity
cscx+cotx-1/cotx-cscx+1 = 1+cosx/sinx
3 answers
asked by
Anonymous
1,763 views
Find a numerical value of one trigonometric function of x if
tanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
1 answer
asked by
Lucy
1,005 views
Prove that if y = cotx then dy/dx = - (cscx)^2. Hint: cotx = cosx/sinx
1 answer
asked by
help me pls
485 views
I can't seem to prove these trig identities and would really appreciate help:
1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1:
1 answer
asked by
Heather
1,327 views
hello
i know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this
1 answer
asked by
CALLIE CALC
690 views
square root of (1-cosx/1+cosx) = cscx - cotx
prove the identity
0 answers
asked by
Manny
547 views