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(100g)(.473J/g°C)(x-62°C) =-(500g)(4.184J/g°C)(x-22°C) Q = mass•specific
(100g)(.473J/g°C)(x-62°C) =-(500g)(4.184J/g°C)(x-22°C)
Q = mass•specific heat•change in temperature Can someone show me
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