Question

7. A 100g mass of tungsten at 100 degrees C is placed in 200 mL of water at 20 degrees C. The mixture reaches equilibrium at 21.6 degrees C. Calculate the specific heat of tungsten.

Ok, I tried working it out but I got

q= 100g x 4.186 j/g*degrees C * (21.6 degrees C- 20.0 degrees C) which equals to 1.6.

So q= 100g * 4.186 j/g*deg C * 1.6

I got a very high number. I am stuck what do I do?

Answer 1

heat lost by tungsten + heat gained by water = 0
Is that hint good enough?

Answer 2

From what I am learning right now you should be using kilos, that would definitely affect your answer.