A metal bar of mass 100g is warmed from 20°c to 80°c. How much heat is absorbed by the metal bar if the specific heat capacity of this metal is 450J/Kg K.

Answer 1

The equation for specific heat capacity = E = m × c × θ
E = 100g x 450J/Kg x 60° (the temperature change) = 2,700,000J

Answer 2

Hmmmm E = 100g x 450J/Kg x 60°
E = .1kg x 450J/Kg x 60°=2700Joules

Answer 3

E=100g×450J/kg×60°
E=2,700,000J

Answer 4

Q=mc(change In tempreture)
Q=0.1kg*450J/kg.k*60k
Q=2700J

Answer 5

2700j

Answer 6

Correct!