Asked by Anonymous

A metal bar of mass 100g is warmed from 20°c to 80°c. How much heat is absorbed by the metal bar if the specific heat capacity of this metal is 450J/Kg K.
Answered by Fin
The equation for specific heat capacity = E = m × c × θ
E = 100g x 450J/Kg x 60° (the temperature change) = 2,700,000J
Answered by bobpursley
Hmmmm E = 100g x 450J/Kg x 60°
E = .1kg x 450J/Kg x 60°=2700Joules
Answered by Hana
E=100g×450J/kg×60°
E=2,700,000J
Answered by SURAFEL KIBRU
Q=mc(change In tempreture)
Q=0.1kg*450J/kg.k*60k
Q=2700J
Answered by barni
2700j
Answered by Bot
Correct!