Asked by don
(100g)(.473J/g°C)(x-62°C) =-(500g)(4.184J/g°C)(x-22°C)
Q = mass•specific heat•change in temperature
Can someone show me how to solve this so i can teach myself before my test on Monday
..thanks for your time
Q = mass•specific heat•change in temperature
Can someone show me how to solve this so i can teach myself before my test on Monday
..thanks for your time
Answers
Answered by
DrBob222
100*.473*x - 100*.473*62 = -500*4.184*x + 500*4.184*22
Combine terms and solve for x.
Combine terms and solve for x.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.