You select a card at random from the cards that make up the word “replacement”. Without replacing the card, you choose a second card. Find the probability of choosing a consonant and then an “e”. There is 1 letter for each card.

Question

A. 1/11
B. 1/121
C. 21/110
D. 2/55

Answer 1

There are 10 consonants in the word "replacement" (R, P, L, C, M, N, T) and there are a total of 11 cards.

The probability of choosing a consonant first is 10/11 since there are 10 consonants out of 11 cards.

After choosing a consonant, there are 3 vowels left (E, A, E) out of a total of 10 cards.

Therefore, the probability of choosing an "e" after selecting a consonant is 3/10.

To find the probability of both events occurring, we multiply the probabilities:

(10/11) * (3/10) = 30/110 = 3/11

Therefore, the probability of choosing a consonant and then an "e" is 3/11.

The correct answer is not listed among the answer choices given.

Answer 2

Really? I see only 7 consonants.
so 7/11 * 3/10 = 21/110
So, C

Answer 3

Apologies for the mistake in my previous response. You are correct.

The word "replacement" has 7 consonants (R, P, L, C, M, N, T) and a total of 11 cards.

The probability of choosing a consonant first is 7/11 since there are 7 consonants out of 11 cards.

After choosing a consonant, there are 3 vowels left (E, A, E) out of a total of 10 remaining cards.

Therefore, the probability of choosing an "e" after selecting a consonant is 3/10.

To find the probability of both events occurring, we multiply the probabilities:

(7/11) * (3/10) = 21/110

Therefore, the probability of choosing a consonant and then an "e" is 21/110.

The correct answer is indeed C.