James has 5 baseball cards, 3 football cards, and 1 hockey card (all different). He picks 2 cards at random without replacement. How many possible outcomes (card combinations) are there?
72
9
81
15
*i think theirs 72 but not sure
4 answers
Multiply 5 and 3 and the answer to that multiply by 1
You can also do 3x5x1 or any way because you will get the same answer.
no
The order in which the cards are drawn should not matter.
They even used the word "combination", which implies that the order does not matter.
So you are simply choosing 2 of the 9 cards
= C(9,2)
= 9!/(2!7!)
= 36
The answer of 72 would be correct if the order in the card does matter.
But suppose you draw one of the baseball cards and the hockey card,
or you draw the hockey card, then the same baseball card.
Would you not have the same combination??
None of the given answers are correct.
The order in which the cards are drawn should not matter.
They even used the word "combination", which implies that the order does not matter.
So you are simply choosing 2 of the 9 cards
= C(9,2)
= 9!/(2!7!)
= 36
The answer of 72 would be correct if the order in the card does matter.
But suppose you draw one of the baseball cards and the hockey card,
or you draw the hockey card, then the same baseball card.
Would you not have the same combination??
None of the given answers are correct.
wtf lol
1 answer