To find the probability of choosing a consonant and then an "e" without replacement, we need to calculate the probability of each event separately and then multiply them together.
First, let's determine the number of consonants in the word "replacement".
The consonants are: r, p, l, c, m, n, and t. There are 7 consonants in total.
The total number of cards in the word "replacement" is 11.
So, the probability of choosing a consonant on the first draw is 7/11.
After selecting a consonant, there are now 10 cards remaining in the word "replacement".
Now, let's determine the number of "e"s in the remaining cards.
There are 2 "e"s in the word "replacement".
Thus, the probability of choosing an "e" on the second draw, given that we already selected a consonant, is 2/10.
To find the overall probability, we multiply the probabilities of the two events:
(7/11) * (2/10) = 14/110 = 7/55
Therefore, the probability of selecting a consonant and then an "e" without replacement from the word "replacement" is 7/55.
You select a card at random from the cards that make up the word “replacement”. Without replacing the card, you choose a second card. Find the probability of choosing a consonant and then an “e”. There is 1 letter for each card.
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Apologies for the mistake in my previous response. Let's calculate the correct probability.
In the word "replacement", there are 4 consonants: r, p, l, and c.
The total number of cards in the word "replacement" is 11.
So, the probability of choosing a consonant on the first draw is 4/11.
After selecting a consonant, there are now 10 cards remaining in the word "replacement".
Now, let's determine the number of "e"s in the remaining cards.
There are 3 "e"s in the word "replacement".
Thus, the probability of choosing an "e" on the second draw, given that we already selected a consonant, is 3/10.
To find the overall probability, we multiply the probabilities of the two events:
(4/11) * (3/10) = 12/110 = 6/55
Therefore, the correct probability of selecting a consonant and then an "e" without replacement from the word "replacement" is 6/55.
In the word "replacement", there are 4 consonants: r, p, l, and c.
The total number of cards in the word "replacement" is 11.
So, the probability of choosing a consonant on the first draw is 4/11.
After selecting a consonant, there are now 10 cards remaining in the word "replacement".
Now, let's determine the number of "e"s in the remaining cards.
There are 3 "e"s in the word "replacement".
Thus, the probability of choosing an "e" on the second draw, given that we already selected a consonant, is 3/10.
To find the overall probability, we multiply the probabilities of the two events:
(4/11) * (3/10) = 12/110 = 6/55
Therefore, the correct probability of selecting a consonant and then an "e" without replacement from the word "replacement" is 6/55.
4 answers