You reach out a second-story window that is 17 m above the sidewalk and throw a 2-kg ball straing upward with 17 J of kinetic energy.

Question

Use g = 10m/s^2

Part A) What is the ball's gravitational potential energy when it is released? Use a height measured from the sidewalk.
PE1 = m_ball*g*h_1 =_____________ Joules

Part B) What is the ball's gravitational potential energy just before hitting the sidewalk? Use a height measured from the sidewalk.
PE} = m_ball*g*h_2 =_____________ Joules

Part C) What is the ball's kinetic energy just before hitting the sidewalk? Since we have the conservation of energy we can assume that the energy from the beginning can convert to the final energy.
KE2 = PE1 + KE1 =
________________Joules

Answer 1

A ) m g h = 2 * 10 * 17 = 340 Joules
B ) zero
C ) at top Ke = 17 and Pe = 340
so at bottom where Pe = 0 then Ke = 357

I do not understand why you are asking because the problem leads you step by step to the solution.