You throw a ball downward from a window at a speed of 2.0 m/s. How fast (in m/s) will it be moving when it hits the sidewalk 2.5 m below?

Answer 1

Vf=√(Vi^2 + 2ad)

Where

Vi=2.0m/s
A=9.8m/s^2
D=2.5m

Answer 2

h = -1/2 g t^2 - Vo t + 2.5 = -4.9 t^2 - 2.0 t + 2.5

set h = 0 , and solve for t (the time of flight)

Vf = Vo + g t

Answer 3

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