Question
You pick a card at random. Without putting the first card back, you pick a second card at random.
1
2
3
What is the probability of picking a 2 and then picking a 1?
Write your answer as a fraction or whole number.
Answers
There are no human answers yet.
Answered by
GPT 3.5
Since we're drawing without replacing the first card, we have to consider the order of the cards being drawn.
There are a total of 3 cards, and in order to pick a 2 and then a 1, the first card must be a 2 and the second card must be a 1.
The probability of picking a 2 on the first draw is 1/3.
After picking a 2, there is 1 remaining card that is a 1 out of the 2 remaining cards. So the probability of picking a 1 on the second draw, given that a 2 was picked on the first draw, is 1/2.
Therefore, the probability of picking a 2 and then a 1 is (1/3) * (1/2) = 1/6.
So, the probability of picking a 2 and then picking a 1 is 1/6.
There are a total of 3 cards, and in order to pick a 2 and then a 1, the first card must be a 2 and the second card must be a 1.
The probability of picking a 2 on the first draw is 1/3.
After picking a 2, there is 1 remaining card that is a 1 out of the 2 remaining cards. So the probability of picking a 1 on the second draw, given that a 2 was picked on the first draw, is 1/2.
Therefore, the probability of picking a 2 and then a 1 is (1/3) * (1/2) = 1/6.
So, the probability of picking a 2 and then picking a 1 is 1/6.
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