Since we're drawing without replacing the first card, we have to consider the order of the cards being drawn.
There are a total of 3 cards, and in order to pick a 2 and then a 1, the first card must be a 2 and the second card must be a 1.
The probability of picking a 2 on the first draw is 1/3.
After picking a 2, there is 1 remaining card that is a 1 out of the 2 remaining cards. So the probability of picking a 1 on the second draw, given that a 2 was picked on the first draw, is 1/2.
Therefore, the probability of picking a 2 and then a 1 is (1/3) * (1/2) = 1/6.
So, the probability of picking a 2 and then picking a 1 is 1/6.
You pick a card at random. Without putting the first card back, you pick a second card at random.
1
2
3
What is the probability of picking a 2 and then picking a 1?
Write your answer as a fraction or whole number.
1 answer