There are a total of 4 cards.
The probability of picking a 5 on the first draw is 1/4.
Since the first card is not put back, there are now only 3 cards left and only 1 of them is a 4.
Therefore, the probability of picking a 4 on the second draw is 1/3.
To find the overall probability, you multiply the probabilities of each event happening:
1/4 * 1/3 = 1/12
So, the probability of picking a 5 and then picking a 4 is 1/12.
You pick a card at random. Without putting the first card back, you pick a second card at random.
Numbers on cards: 2 3 4 5
What is the probability of picking a 5 and then picking a 4?
11 answers
You flip a coin twice. What is the probability of getting tails and then getting heads? write your answer as a percentage.
When you flip a coin, there are two possible outcomes - heads or tails.
The probability of getting tails on the first flip is 1/2.
After the first flip, you still have 2 possible outcomes, but only one will result in a head.
So, the probability of getting heads on the second flip is 1/2.
To find the overall probability of getting tails and then heads, you multiply the probabilities of each event happening:
1/2 * 1/2 = 1/4 = 0.25
Therefore, the probability of getting tails and then getting heads when flipping a coin twice is 0.25, which is equivalent to 25%.
The probability of getting tails on the first flip is 1/2.
After the first flip, you still have 2 possible outcomes, but only one will result in a head.
So, the probability of getting heads on the second flip is 1/2.
To find the overall probability of getting tails and then heads, you multiply the probabilities of each event happening:
1/2 * 1/2 = 1/4 = 0.25
Therefore, the probability of getting tails and then getting heads when flipping a coin twice is 0.25, which is equivalent to 25%.
You spin the spinner twice.
Numbers on spinner: 3 4 5 6 7 8
What is the probability of landing on a number greater than 5 and then landing on 4? write your answer as a fraction or whole number.
Numbers on spinner: 3 4 5 6 7 8
What is the probability of landing on a number greater than 5 and then landing on 4? write your answer as a fraction or whole number.
There are a total of 6 numbers on the spinner.
The numbers greater than 5 are 6, 7, and 8, so there are 3 favorable outcomes.
The probability of landing on a number greater than 5 on the first spin is 3/6 or 1/2.
After the first spin, the spinner is not reset, so there are still 6 numbers on the spinner, with only one of them being a 4.
Therefore, the probability of landing on a 4 on the second spin is 1/6.
To find the overall probability of landing on a number greater than 5 and then landing on 4, you multiply the probabilities of each event happening:
1/2 * 1/6 = 1/12
So, the probability of landing on a number greater than 5 and then landing on 4 when spinning the spinner twice is 1/12.
The numbers greater than 5 are 6, 7, and 8, so there are 3 favorable outcomes.
The probability of landing on a number greater than 5 on the first spin is 3/6 or 1/2.
After the first spin, the spinner is not reset, so there are still 6 numbers on the spinner, with only one of them being a 4.
Therefore, the probability of landing on a 4 on the second spin is 1/6.
To find the overall probability of landing on a number greater than 5 and then landing on 4, you multiply the probabilities of each event happening:
1/2 * 1/6 = 1/12
So, the probability of landing on a number greater than 5 and then landing on 4 when spinning the spinner twice is 1/12.
You roll a 6-sided die two times. What is the probability of rolling an odd number and then rolling an odd number. Write your answer as a percentage.
When rolling a fair 6-sided die, there are 3 odd numbers (1, 3, and 5) and 3 even numbers (2, 4, and 6).
The probability of rolling an odd number on the first roll is 3/6 or 1/2.
After the first roll, the die is not reset, so there are still 6 possible outcomes on the second roll, and 3 of them are odd numbers.
Therefore, the probability of rolling an odd number on the second roll is 3/6 or 1/2.
To find the overall probability of rolling an odd number and then rolling an odd number, you multiply the probabilities of each event happening:
1/2 * 1/2 = 1/4 = 0.25
So, the probability of rolling an odd number and then rolling an odd number when rolling a 6-sided die two times is 0.25, which is equivalent to 25%.
The probability of rolling an odd number on the first roll is 3/6 or 1/2.
After the first roll, the die is not reset, so there are still 6 possible outcomes on the second roll, and 3 of them are odd numbers.
Therefore, the probability of rolling an odd number on the second roll is 3/6 or 1/2.
To find the overall probability of rolling an odd number and then rolling an odd number, you multiply the probabilities of each event happening:
1/2 * 1/2 = 1/4 = 0.25
So, the probability of rolling an odd number and then rolling an odd number when rolling a 6-sided die two times is 0.25, which is equivalent to 25%.
You pick a card at random. Without putting the first card back, you pick a second card at random.
Number on cards: 3 4 5 6 7 8 9
What is the probability of picking an even number and then picking an even number?
Number on cards: 3 4 5 6 7 8 9
What is the probability of picking an even number and then picking an even number?
When picking a card out of the 7 possible cards, there are 4 even numbers (4, 6, 8) and 3 odd numbers (3, 5, 7, 9).
The probability of picking an even number on the first draw is 4/7.
After the first draw, the card is not put back, so there are now 6 remaining cards left with 3 even numbers.
Therefore, the probability of picking an even number on the second draw is 3/6 or 1/2.
To find the overall probability of picking an even number and then picking an even number, you multiply the probabilities of each event happening:
4/7 * 1/2 = 2/7
Therefore, the probability of picking an even number and then picking an even number when picking cards from the deck twice is 2/7.
The probability of picking an even number on the first draw is 4/7.
After the first draw, the card is not put back, so there are now 6 remaining cards left with 3 even numbers.
Therefore, the probability of picking an even number on the second draw is 3/6 or 1/2.
To find the overall probability of picking an even number and then picking an even number, you multiply the probabilities of each event happening:
4/7 * 1/2 = 2/7
Therefore, the probability of picking an even number and then picking an even number when picking cards from the deck twice is 2/7.
You spin a spinner
numbers on spinner: 1-8
What is the probability of landing on an even number and then landing on an even number?
numbers on spinner: 1-8
What is the probability of landing on an even number and then landing on an even number?
When spinning the spinner with numbers 1-8, there are 4 even numbers (2, 4, 6, 8) and 4 odd numbers (1, 3, 5, 7).
The probability of landing on an even number on the first spin is 4/8 or 1/2.
After the first spin, the spinner is not reset, so there are still 8 possible outcomes on the second spin, and 4 of them are even numbers.
Therefore, the probability of landing on an even number on the second spin is 4/8 or 1/2.
To find the overall probability of landing on an even number and then landing on an even number, you multiply the probabilities of each event happening:
1/2 * 1/2 = 1/4
Therefore, the probability of landing on an even number and then landing on an even number when spinning the spinner twice with numbers 1-8 is 1/4.
The probability of landing on an even number on the first spin is 4/8 or 1/2.
After the first spin, the spinner is not reset, so there are still 8 possible outcomes on the second spin, and 4 of them are even numbers.
Therefore, the probability of landing on an even number on the second spin is 4/8 or 1/2.
To find the overall probability of landing on an even number and then landing on an even number, you multiply the probabilities of each event happening:
1/2 * 1/2 = 1/4
Therefore, the probability of landing on an even number and then landing on an even number when spinning the spinner twice with numbers 1-8 is 1/4.