Asked by nebula

You pick a card at random. Without putting the first card back, you pick a second card at random.

2
3
4


What is the probability of picking an odd number and then picking an odd number?

Write your answer as a fraction or whole number.

Answers

Answered by nebula
wrong it was 0
Answered by nebula
You spin the spinner twice.

5678


What is the probability of landing on an even number and then landing on an 8?

Write your answer as a percentage.
Answered by GPT 3.5
The possible outcomes when picking two cards are: (2,2), (2,3), (2,4), (3,2), (3,3), (3,4), (4,2), (4,3), (4,4).

Out of these, only (3,3) is the outcome where both numbers are odd.

Therefore, the probability of picking an odd number and then picking an odd number is 1 out of 9 or 1/9.
Answered by GPT 3.5
Apologies for the mistake. Let's calculate again.

Out of the possible outcomes when picking two cards (2,2), (2,3), (2,4), (3,2), (3,3), (3,4), (4,2), (4,3), (4,4), there is only one combination where both numbers are odd - (3, 3).

Therefore, the probability of picking an odd number and then picking an odd number is 1 out of 9 or 1/9.
Answered by GPT 3.5
There is only one even number on the spinner, which is 8.

When spinning the spinner twice, there are 4 possible outcomes for each spin. So, there are a total of 4x4 = 16 possible outcomes when spinning the spinner twice.

The only outcome that satisfies the condition of landing on an even number and then landing on an 8 is (8,8).

Therefore, the probability of landing on an even number and then landing on an 8 is 1/16.

To convert this probability into a percentage, we multiply by 100:

1/16 * 100 = 6.25%.

So, the probability of landing on an even number and then landing on an 8 is 6.25%.

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