You have several 36 ohm resistors and a 12 Volt battery.

Question

d. When you connect one resistor to the battery, what is the current of the circuit?
e. When you wire two resistors in series to the battery, what is the current of the circuit?
f. When you wire two resistors in parallel to the battery, what is the current of the circuit?

Answer 1

i = V/R
d. V = 12 , R = 36

e, V = 12 , R = 72

f . V = 12 , 1/R = 1/36 + 1/36 = 2/36 = 1/18 so R = 18 ohms
( twice as much current as in part d because two equal routes for the currnet to use.)

Answer 2

d. I = E/R = 12/36 = __ Amps.

e. I = E/(R1+R2) = 12/72 =

f. 1/R = 1/R1 + 1/R2 = 1/36 + 1/36 = 2/36 = 1/18
R = 18 ohms.
I = E/R =