Ask a New Question
Search
Questions and answers by
henry2,
Answers (109)
Compost = X kg. Potting = 5x kg. x + 5x = 6 X = 1 kg. sx = 5 kg.
Correction: Z = R = 10 ohms. P = 100^2/10 = 1000 W.
At the resonant frequency: Xl = -Xc Xl+Xc = 0. Therefore, Z = R = 116 ohms. P = E^2/R = 100^2/116 = 86.2 W.
At resonance: I = V/R = 60/116 = 0.52A. Xl = Vl/I = 40/0.52 = 77.3 ohms. Xl = 2pi*F*L = 77.3 6.28*5.1*10^5L = 77.3 L = 2.41*10^-5 h. At -45 degrees: Xl = R = 116 ohms. Xl = 2pi*F*L = 116 6.28*F*2.41*10^-5 = 116 F = 7.65*10^5 rad/s.
I = 0.707 * 1 = 0.707A rms. P = I^2*R = (0.707)^2 * 51 = 25.5 kW.
I = 0.707*4 = 2.828A rms. P = I^2*R = (2.828)^2 * 60 = 480 kW.
A(2, 3), M(x, y), B(4, -5). x-2 = 1/2(4-2) X = 3. y-3 = 1/2(-5-3) Y =
All angles are measured CW from +y-axis. Given: AB = 60 km[60o], AC = 100 km[290o], BC = ? BC = BA + AC = 60[60+180] + 100[290o] BC = ( 60*sin240+100*sin290) + (60*cos240+100*cos290)I BC = -146 + 4.2i = 146.1km[-88] = 146.1km[272o]. CB = 146.1km[272-180] =
10:35-8:15 = 2:20 = 2.33 h. delay. 90T + 110(T-2.33) = 360 200T-256 = 360 T = 3.08 h. d = 90 * 3.08 = 277 km from Town A. t
Right!
H(5, 13), M(x, y), K(7, 5). x-5 = 1/2(7-5) X = 6. y-13 = 1/2(5-13). Y =
Series connection: R1 = R2 = 88/2 = 44 ohms.
sin A = y/r = sqrt2/2 x^2 + y^2 = r^2 x^2 + 2 = 4 X = sqrt2. Cos A = x/r = sqrt2/2.
Cos A = x/r = -1/2 x^2 + y^2 = r^2 (-1)^2 + y^2 = 2^2 Y = sqrt3. Tan A = y/x = sqrt3/-1 = -sqrt3.
4^(4m) = 262,144 4m*Log4 = Log262144 Divide both sides by Log 4: 4m = 9 m = 9/4.
Yes.
M*g = 55*9.8 = 539 N. Fs = u*Fn = 0.67 * 539 = 361 N. = Force of static friction. F-Fs = M*a. F - 361 = M*0 F = 361 N.
(500-400)/5 = $20/yr., increase. (400-500)/5 = -$20/yr., decrease.
I = E/Z = 90/120 = 0.75A. P = I^2*R = 0.75^2 * 64 = ___ Watts.
V = pi*r^2*h = 3.14*10^2*13.5 = ___ cm^3.
16 7/36 yds. = 16.194 yds. 16.194 - 8.666 = 7.53 yds. left.
Cube root of 900 m^3 = 900^(1/3) = 9.65489385. So it is not a perfect cube.
S^3 = 729 S = 9 = Length of each side. A = 4*(L*h) = 4*(9*9) = 324 = Area of the 4 walls. Aw = 324/3 = 108 = Total area of the windows.
Correction: 7/3 * 14.50 = $33.83 Cost = 33.83 + 0.07*33.83 =
C = 7/3 * 14.50 =
Vo = 35Ft./s[40o] Xo = 35*cos40 = 26.8 m/s. d = Xo*T = 40 26.8*T = 40 T =
a. V = Vo + g*T = 0 88 + (-32)T = 0 T = b. V^2 = Vo^2 + 2g*h = 0 88^2 + (-64)h = 0 h = 121 Ft. above launching point. ho+h = 4 + 121 = 125 Ft. above gnd.
(y+10) + (y+5) + (2y-40) + (y-25) = 360 5y +10 + 5 - 40 - 25 = 360 Y =
7/50 = x/1000. X = (7/50) * 1000 =
5. E1 = 60V., E2 = 30V. 10I2 - 0.6I1 = 30 Eq1: - 0.6I1 + 10I2 = 30. 30 + 0.6I1 + 0.5(I1+I2) = 60 Eq2: 1.1I1 + 0.5I2 = 30. Multiply Eq1 by 1.1 and Eq2 by 0.6: -0.66I1 + 11I2 = 33 0.66I1 + 0.3I2 = 181 sum: 11.3I2 = 51 I2 = 4.51A. = Load current. In Eq1,
X = u*v/(u+v) X = 3*3/(3+3) = 9/6 = 1.5.
1st. piece = X. 2nd piece = x-4. 3rd piece = x-4-2 = x-6. x + x-4 + x-6 = 50 3x = 60 X = 20 Ft. x-4 = x-6 =
2L + 2W = 200 Eq1: L + W = 100. L*W = 2400 L = 2400/W. 2400/W + W = 100 2400 + W^2 = 100W W^2 - 100W + 2400 = 0 W = (100 +- sqrt(10000-9600))/2 = 60, and 40 Ft. W = 40 Ft., the shortest length. In Eq1, replace W with 40 and solve for L.
h = 0.5g*T^2 = 4 4.9T^2 = 4 T = 0.90 s.
V = Vo + g*Tr = 0 20 + (-9.8)Tr = 0 Tr = 2.04 s. = Rise time. Tf = Tr = 2.04 s. = Fall time. T = Tr+Tf = 2.04 + 2.04 = 4.08 s. = Time in air.
You are welcome.
A(2, 5), B(x, y). m/= 2/3. y-5 = 2, Y = 7. x-2 = 3, X = 5.
All negative numbers are less than zero. All positive numbers are greater than zero. -5 is greater than -10.
4375mi/0.25h = 17,500 mi/h.
a. V = 3 * 0.5kv = b. Q = C*V = 120*10^-12 * 500 = 60*10^3 * 10^-12 = 60^10^-9 C = 60 nC. c. Ceq = 120/3 = 40 pF. Eneroy = Ceq*V/2 = 40*10^-12 * 1500^2/2 = 45*10^-6 J.
23*2^3x = 40. 2^3x = 40/23 = 1.739 3x*Log2 = Log1.739 3x = 0.7984 X = 0.26613.
100% - (7.65+12+8)% = 100% - 27.65% = 72.35%. 0.7235 * 10 = $7.24/h, net. T = 800/7.24 = ___ Hours.
X = 3*Cos20. Y = 3*sin20.
V^2 = Vo^2 + 2a*d = 0 45^2 + 2*(-2)d = 0 d = ___ m.
r * 1075 = 43 r = 43/1075 * 100% = 4 %.
Vo = 60km/h = 60,000m/3600s = 16.7 m/s. V = 36km/h = 36,000m/s/3600s = 10 m/s. V = Vo + a*T = 10 16.7 + (-5)T = 10 T =
(1/2)/3 = 1/2*3 = 1/6.
Disp. = 36i + 25 - 25 = 36i = 36 km N.
X red pens. 6x blue pens. x+4 black pens. x + 6x + x+4 = 84 X = x+4 =
