To find the speed at which both Yobo and Adoki cycle, we need to establish a relation between their distances and time.
-
Speed of Yobo:
- Distance: \( (x - 45) \) km
- Time: 3 hours
- Speed \( V_Y \) = Distance / Time = \( \frac{x - 45}{3} \) km/h
-
Speed of Adoki:
- Distance: \( (x + 15) \) km
- Time: 7 hours
- Speed \( V_A \) = Distance / Time = \( \frac{x + 15}{7} \) km/h
Since they are both cycling at the same rate, we can set their speeds equal to each other:
\[ \frac{x - 45}{3} = \frac{x + 15}{7} \]
Now, let's solve this equation for \( x \).
Cross Multiplying:
\[ 7(x - 45) = 3(x + 15) \]
Expanding Both Sides:
\[ 7x - 315 = 3x + 45 \]
Rearranging the Equation:
\[ 7x - 3x = 315 + 45 \] \[ 4x = 360 \] \[ x = 90 \]
Finding the Speeds:
Now that we have \( x \), we can find the distances and their corresponding speeds.
-
Distance for Yobo:
- \( x - 45 = 90 - 45 = 45 \) km
- Speed of Yobo: \( \frac{45}{3} = 15 \) km/h
-
Distance for Adoki:
- \( x + 15 = 90 + 15 = 105 \) km
- Speed of Adoki: \( \frac{105}{7} = 15 \) km/h
Thus, both Yobo and Adoki cycle at a speed of 15 km/h.
If you have specific questions or additional information to discuss regarding Yobo and Adoki, please let me know!