note that angle ZXY is a right angle.
(a) |YZ| = 100
(b) from Y, ∆y/∆x = (-20/√2)/(-140/√2) = 1/7
the reference angle is 8.13°
So, referring to your diagram, the bearing of Z from Y is 270-8.13 = 261.87°
Y is 60km away from x on a bearing of 135 degrees. Z is 80km away from x on a bearing of 225 degrees. Find
a. The distance of z from y
b. The bearing of z from y
3 answers
All angles are measured CW from +Y axis
a. d = 80km[225o] - 60km[135o].
d = -56.6-56.6i - (42.4-42.4i) = -99 - 14i = 58.3 km.
b. TanA = X/Y = -99/-14.
A = 76o W. of S. = 256o CW.
a. d = 80km[225o] - 60km[135o].
d = -56.6-56.6i - (42.4-42.4i) = -99 - 14i = 58.3 km.
b. TanA = X/Y = -99/-14.
A = 76o W. of S. = 256o CW.
Correction:
a. d = -99 - 14i = 100 km.
b. A = 82o W. of S. = 262o CW from +y-axis.
a. d = -99 - 14i = 100 km.
b. A = 82o W. of S. = 262o CW from +y-axis.
1 answer