Question

y is 60km away from x on a bearing of 135 degree.Z is 80km away from x on a bearing of 225 degree find (a)distance of z from y (b) bearing of z from y

Answer 1

angle YXZ is 90° so YZ = 100 (3-4-5 triangle)
relative to X,
Y = (60/√2 , -60/√2)
Z = (-80/√2 , -80/√2)
so, relative to Y, Z is at (-140/√2, -20/√2) for a bearing of
270° - arctan(1/7) = 261.86°

Answer 2

a. d = 80km[225] - 60km[135o].
X = 80*sin225 - 60*sin135 = -99 km.
Y = 80*Cos225 - 60*Cos135 = -14 km.
d = sqrt(X^2 + Y^2) = 100 km.

b. Tan A = X/Y.
A = 82o W of S. = 262o CW from +y-axis(bearing).

Answer 3

Y is 60km away from X on a bearing of one hundred and thirty five degree z is 80km away from X on a bearing of two hundred and twenty five degree . Find the distance z from y

Answer 4

I did not know it,pls explain it to me and give me the solution

Answer 5

Pls explain to me