(x-3)^2+(x+2)^2=17
How do I solve for x?
4 answers
expand the two binomials, combine like terms, then put it in the form of a quadratic...you can then use the quadratic equation, or perhaps factor to find x.
here is what i got:
(x-3)(x-3)+(x+2)(x=2=17
2x^2-2x=22
x=11
Does that seem right?
(x-3)(x-3)+(x+2)(x=2=17
2x^2-2x=22
x=11
Does that seem right?
(x-3)^2+(x+2)^2=17
x^2 -6 x + 9 + x^2 + 4 x + 4 -17 = 0
2 x^2 -2 x -4 = 0
(2x-4)(x+1) = 0
x = 4/2 = 2
or
x = -1
x^2 -6 x + 9 + x^2 + 4 x + 4 -17 = 0
2 x^2 -2 x -4 = 0
(2x-4)(x+1) = 0
x = 4/2 = 2
or
x = -1
thank you very much for all your help, you really help by showing how to solve for x rather than just tell me what to do. I have a better understanding.
1 answer