x^2 + 2x + 2 = 0
I would use "completing the square"
x^2 + 2x = -2
x2 + 2x + 1 = -2+1
(x+1) = -1
x+1 = ±√-1, remember √-1 = i
x = -1 ± i
x^2 + 2x + 2 = 0
The answer has an imaginary number in it which we're supposed to solve for, but I'm having trouble with it.
Thanks for any help!
2 answers
(x^2 + 2x + 2) -1 = (0)-1
x^2 + 2x +1 = -1
(x + 1)(x + 1) = -1
(x +1)^2 = -1
(x +1) = sr(-1) (sr squareroot of)
x = -1 + sr(-1)
x^2 + 2x +1 = -1
(x + 1)(x + 1) = -1
(x +1)^2 = -1
(x +1) = sr(-1) (sr squareroot of)
x = -1 + sr(-1)