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[x^5*(-3)*[(x^2+1)^-4]*(2x)]-{[(x^2+1)^-3]*[(5)x^4]} / [ (x^5)^2 ] = {(-3)*(2x)*(x^5)*[(x^2+1)^-4]}-{(5)+(x^4)*[((x^2)+1)^-3] / (x^7) = (-6)*(x^6)*[((x^2)+1)^-4]-{(5)*(x^4)*[(x^2+1)^-3] / (x^7) = {[(-6)*(x^6)*[((x^2)+1)^-4]]/x^7}-[{(5)*(x^4)*[(x^2+1)^-3]
1 - (1/5)^2 = 96% 1 - (1/25) = 96% (25/25) - (1/25) = 96% (24/25) = 96% 0.96 = 96% (0.96) 100% = 96% 96% = 96%
assume x is the undiscounted price 100% of x - 10% of x = 72 1.00x - 0.10x = 72 x (1.00-0.10) = 72 x (0.90) = 72 x = 72 / 0.90 x = 80 Regular price is $80.00
using the slope-intercept equation y = mx + b (where m is the slope and b is y-intercept) y = x +7 (where 1 is the slope and 7 is the y-intercept) Answer: slope is 1
(x^2 + 2x + 2) -1 = (0)-1 x^2 + 2x +1 = -1 (x + 1)(x + 1) = -1 (x +1)^2 = -1 (x +1) = sr(-1) (sr squareroot of) x = -1 + sr(-1)
3 with car in the middle facing opposite direction as two cars
-7, -2, -1, 0, 2

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