First, we need to find the slope of the line using the two points given.
Slope (m) = (y2 - y1) / (x2 - x1)
Slope (m) = (10 - 1) / (5 - 2)
Slope (m) = 9 / 3
Slope (m) = 3
Now that we have the slope, we can use one of the points to find the y-intercept (b) in the equation y = mx + b.
Using point (2,1):
1 = 3(2) + b
1 = 6 + b
b = -5
Therefore, the equation of the linear function passing through the points (2,1) and (5,10) is:
y = 3x - 5
Write the equation of the linear function that passes through the points (2,1) and (5,10).
y = __ x +__
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