Asked by Alice
Which equation models the linear relationship in the table below?
x y
-4 10
1 -5
6 -20
x y
-4 10
1 -5
6 -20
Answers
Answered by
Damon
change in y/change in x
= (-5-10) / (1+4) = -3
or
= (-20+5) / (6-1) = -3
or
= (-20 -10) / (6+4) = -3
remarkable, the slope is constant and is -3
so
y = -3 x + b
now put any of those points in
10 = -3(-4) + b
b = -2
so
y = -3 x - 2
NOW
check that with another point like
-20 = -3(6) - 2 ?????
sure enough
-20 = -20
= (-5-10) / (1+4) = -3
or
= (-20+5) / (6-1) = -3
or
= (-20 -10) / (6+4) = -3
remarkable, the slope is constant and is -3
so
y = -3 x + b
now put any of those points in
10 = -3(-4) + b
b = -2
so
y = -3 x - 2
NOW
check that with another point like
-20 = -3(6) - 2 ?????
sure enough
-20 = -20
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