First, we need to find the slope (m) of the line using the formula:
m = (y2 - y1) / (x2 - x1)
Using the values from the table, we get:
m = (103 - 58) / (20 - 11)
m = 45 / 9
m = 5
Now we can use the slope-intercept form of a line, y = mx + b, and substitute the slope we just found and one of the points from the table (let's use point (11, 58)):
y = 5x + b
Solving for b, we plug in the x and y values from point (11, 58):
58 = 5(11) + b
b = 58 - 55
b = 3
The equation of the linear function that models the relationship is:
y = 5x + 3
Write the equation of the linear function that models the relationship shown in the table. Enter your answer in y = mx + b
x, y
11, 58
20, 103
1 answer