y-4=2(x+3)
is the line parallel to y=2x-5
You want the line perpendicular. So, your equation is
y-4 = -1/2 (x+3)
you can massage that as you will.
Write an equation of the line that passes through (-3,4) and is perpendicular to the line y=2x-5.
Answer:
y-y1=2(x-x1)
y-4=2(x+3)
Is this how I would write my equation or should I distribute the 2 to make it y-4=2x+6?
1 answer
1 answer