Asked by Kerri
I need help with "write in equation in slope-intercept form for the line that is parallel to to the given line line and and that passes through the given point.
y=1/2x=5;(4,-3) How do you find a line that is perpendicular. Please and thank you! :)
y=1/2x=5;(4,-3) How do you find a line that is perpendicular. Please and thank you! :)
Answers
Answered by
Steve
Assuming a typo, and that you mean
y = 1/2 x + 5
the slope is 1/2. Now, using the point-slope form, we want the line
y+3 = 1/2 (x-4)
or
y = 1/2 x -5
A perpendicular line will have slope -1/(1/2) = -2.
use that as you will.
y = 1/2 x + 5
the slope is 1/2. Now, using the point-slope form, we want the line
y+3 = 1/2 (x-4)
or
y = 1/2 x -5
A perpendicular line will have slope -1/(1/2) = -2.
use that as you will.
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