y = mx + b
where m is the slope and b is the y-intercept.
If the trend line passes through point (20, y), the equation becomes:
y = mx + b
We need to find the value of m (the slope) and b (the y-intercept) using the given point.
Since the trend line has a positive linear association, the slope is positive. To find the slope m, we can use the formula:
m = (y2 - y1) / (x2 - x1)
Using the point (0,0) as the second point to find the slope:
m = (y - 0) / (20 - 0)
m = y / 20
So the equation for the trend line passing through the point (20, y) is:
y = (y/20)x + b
or
y = (1/20)x + b
where b is the y-intercept.
Write an equation in slope-intercept form of the trend line.
(1 point)
the positive linear association points on 20
1 answer