y-5 = -4/3 (x+6)
now just convert that to y = mx+b
Write an equation in slope intercept form of the line that is perpendicular to the given line and that passes through the given point
3x-4y=8 ; (-6,5)
3 answers
When I did it I got y=3/4x+9 1/2... Did u get that also ?
y - 5 = -4/3 (x+6)
y - 5 = -4/3 x - 8
y = -4/3 x - 3
the slope has to be -4/3, since the original line had slope 3/4 and you want a perpendicular line.
Your line is parallel to it, not perpendicular.
And, as long as you're doing algebra now, lose the mixed numbers. They're just a nuisance. 19/2 is much more useful in calculations than 9 1/2.
y - 5 = -4/3 x - 8
y = -4/3 x - 3
the slope has to be -4/3, since the original line had slope 3/4 and you want a perpendicular line.
Your line is parallel to it, not perpendicular.
And, as long as you're doing algebra now, lose the mixed numbers. They're just a nuisance. 19/2 is much more useful in calculations than 9 1/2.
1 answer