Hmmm. 1st and 2nd methods?
Not much to go on there ...
Why does the first method for determining volume work only for a regularly shaped object?
Will the second method for determining volume work for any object or just an irregularly shaped one? Why?
Is one method of measurement more accurate than the other? Why or why not?
Would the displacement method of measurement work for a cube of sugar? What about a cork? Why or why not?
What did you find out from this investigation? Be thoughtful in your answer.
4 answers
I suspect that the first method was using dimensions and the shape (rectangular brick or sphere or whatever) . It is hard to use that for a weirdly shaped rock.
I bet the second method was to fill a glass with water and see how much overflows when I slip the rock in. That will work with any old shape but only works for a floating object if you push it below the surface with a needle. If it floats, all you found was the weight (Google Archimedes)
I bet the second method was to fill a glass with water and see how much overflows when I slip the rock in. That will work with any old shape but only works for a floating object if you push it below the surface with a needle. If it floats, all you found was the weight (Google Archimedes)
By the way while I was typing that the sugar dissolved.
i really dont know .help ?
4 answers