When one mole of C6H6 is burned, 3.27 MJ of heat is produced. When the heat from burning 7.59 g of C6H6 is added to 5.69 kg of water at 21.0°C, what is the final temperature of the water?

Answer 1

q=m*c*deltaT

q=heat produced x (7.59)/(molar mass C6H6)

m=mass of water
c=specific heat of water=4.179J/gC
deltaT = T_final - T_initial

T_initial = 20 degreeC

Answer 2

20