How much heat is released? That's
3.27E6 J x (5.35/molar mass C6H6) = ?
Then q = mass H2O x specific heat H2O x (Tfinal-Tinitial).
Convert kg H2O to grams. Use specific heat in J/g*C
When one mole of C6H6 is burned, 3.27 MJ of heat is produced. When the heat from burning 5.35 g of C6H6 is added to 5.69 kg of water at 21.0°C, what is the final temperature of the water?
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