1 mol C6H6 = 78 grams.
Heat generated by 5.43 g is
3.27 MJ x (5.43/78) = ?
Substitute the answer denoted by ? in
? = mass H2O x specific heat H2O x (Tfinal - Tinitial).
Be sure specific heat and mass have appropriate units.
When one mole of C6H6 is burned, 3.27 MJ of heat is produced. When the heat from burning 5.43 g of C6H6 is added to 5.69 kg of water at 21.0°C, what is the final temperature of the water?
1 answer