When copper (II) nitrate reacts with sodium hydroxide, copper (II) hydroxide is produced. How many grams of copper (II) hydroxide can be prepared from 2.7 grams of copper (II) nitrate reacting with sodium hydroxide?

Answer 1

Cu(NO3)2 + 2NaOH ==> Cu(OH)2 + 2NaNO3
Moles Cu(NO3)2 = grams/molar mass = ?
Look at the coefficients in the balanced equation and see 1 mol Cu(OH)2 producerd from 1 mol Cu(NO3)2 used.
Then grams Cu(OH)2 = mols x molar mass = ?
Post your work if you get stuck.