Asked by Ethan
When copper(II) nitrate reacts with sodium hydroxide, copper (II) hydroxide is produced. How many grams of Cu(OH)2 can be prepared from 12.7g of Cu(NO3)2 and excess NaOH?
Answers
Answered by
DrBob222
This four step process will work all of your stoichiometry problems. Copy and save this.
1. Write and balance the equation.
Cu(NO3)2 + 2NaOH ==> Cu(OHN)2 + 2NaNO3
2. Convert grams of what you have to mols.
mols = grams/molar mass = ?
3. Using the coefficients in the balanced equation, convert mols of what you have [in this case mols Cu(NO3)2] to mols of what you want [in this case Cu(OH)2].
4. Now convert mols Cu(OH)2 to grams.
grams = mols x molar mass
Post your work if you get stuck.
1. Write and balance the equation.
Cu(NO3)2 + 2NaOH ==> Cu(OHN)2 + 2NaNO3
2. Convert grams of what you have to mols.
mols = grams/molar mass = ?
3. Using the coefficients in the balanced equation, convert mols of what you have [in this case mols Cu(NO3)2] to mols of what you want [in this case Cu(OH)2].
4. Now convert mols Cu(OH)2 to grams.
grams = mols x molar mass
Post your work if you get stuck.
Answered by
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