Asked by stocihs hard
Lead(II) nitrate reacts with potassium iodine to produce lead(II) iodide and Potassium nitrate. If 1.23 mg of lead nitrate are consumed, what is the mass of the potassium nitrate produced?
Answers
Answered by
DrBob222
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3
Convert 1.23 mg Pb(NO3)2 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles Pb(NO3)2 to moles KNO3.
Now convert moles KNO3 to grams. g = moles x molar mass.
Convert 1.23 mg Pb(NO3)2 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles Pb(NO3)2 to moles KNO3.
Now convert moles KNO3 to grams. g = moles x molar mass.
Answered by
Anonymous
It is reversible I am a high school teacher
Answered by
Francesca`
7.42
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