Asked by stocihs hard

Lead(II) nitrate reacts with potassium iodine to produce lead(II) iodide and Potassium nitrate. If 1.23 mg of lead nitrate are consumed, what is the mass of the potassium nitrate produced?

Answers

Answered by DrBob222
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3

Convert 1.23 mg Pb(NO3)2 to moles. moles = grams/molar mass

Using the coefficients in the balanced equation, convert moles Pb(NO3)2 to moles KNO3.

Now convert moles KNO3 to grams. g = moles x molar mass.
Answered by Anonymous
It is reversible I am a high school teacher
Answered by Francesca`
7.42

Related Questions