Lead(II) nitrate reacts with potassium iodine to produce lead(II) iodide and Potassium nitrate. If 1.23 mg of lead nitrate are consumed, what is the mass of the potassium nitrate produced?

Answer 1

Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3

Convert 1.23 mg Pb(NO3)2 to moles. moles = grams/molar mass

Using the coefficients in the balanced equation, convert moles Pb(NO3)2 to moles KNO3.

Now convert moles KNO3 to grams. g = moles x molar mass.

Answer 2

It is reversible I am a high school teacher

Answer 3

7.42