When a 58 gram tennis ball is served, it accelerates from rest to a speed of 45 m/s. The impact with the racket gives the ball a constant acceleration over a distance of 44 cm. What is the magnitude of the net force acting on the ball?

Answer 1

m=58gm=0.058kg, u=0, V=45m/s, s=44cm=0.44m
so, v^2=u^2+2*a*s
a=2301.136m/s^2
F=ma
F=0.058*2301.136=133.466N
check it if correct