What would be the correct way to arrange this?

Question

Consider the reaction below.
3K2C2O4(aq)+2Fe(NO3)3(aq)->Fe2(C2O4)3(s)+6KNO3(aq)
What mass in grams of K2C2O4 (MM=166.22g/mole)will react completely with 35.0mL of 0.800M Fe(NO3)3?

Answer 1

mols Fe(NO3)3 = M x L = ?
Convert mols Fe(NO3)3 to mols K2C2O4 using the coefficients in the balanced equation.
Then grams K2C2O4 = mols x molar mass = ?