What volume of 0.200 M K2C2O4 is required to completely react with 30.0 mL of 0.100 M Fe(NO3)3?

Question

2Fe(NO3)3 + 3K2C2O4 --> Fe2(C2O4)3 + 6KNO3

Answer 1

mols Fe(NO3)3 = M x L = ?
Use the coefficients in the balanced equation to convert mols Fe(NO3)3 to mols K2C2O4.
Then M K2C2O4 = mols K2C2O4/L K2C2O4. You know mols and M, solve for L and convert to mL if needed. Post your work if you get stuck.