Asked by Student
How do I calculate the mass of oxalate (c2o42-) given the following numbers in the equation;
0.0003084 mol x 88.02 g (c2o4-2)/moles of (c2o4-2) ?
0.0003084 mol x 88.02 g (c2o4-2)/moles of (c2o4-2) ?
Answers
Answered by
oobleck
just watch the units:
moles * g/mole = g
= 0.0003084 * 88.02 = ____
moles * g/mole = g
= 0.0003084 * 88.02 = ____
Answered by
Student
Would the mass of oxalate be 0.02714536?
Answered by
Student
Sorry I mean would the moles of oxalate be 0.02714536?
Answered by
DrBob222
That number looks OK to me; however, that many figures is jut a readout on your calculator dial. You're allowed 4 significant figures so I would round that to
0.02714536 = 0.02714 and for rounding that 5 I use "when rounding a 5 round to the nearest even number".
0.02714536 = 0.02714 and for rounding that 5 I use "when rounding a 5 round to the nearest even number".
Answered by
DrBob222
BTW, that's not mols, that's grams of oxalate.
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