14-pH=pOH=14-10.5=3.5
pOH=-log[OH-]=3.5
10^-(pOH)=10^-(3.5)=OH concentration in M
4.40L*(OH concentration in M)= moles of OH
moles of OH*(39.997 g/mol)= mass of NaOH needed
mass of NaOH needed
Since 15% is 0.15g of NaOH/g of solution, solving for g of solution
mass of NaOH needed/(0.15g of NaOH/g of solution)= g of solution needed.
g of solution needed/1.116 g/mL= volume in mL
Report your answer with 3 sig figs.
What volume of a 15.0% by mass NaOH solution, which has a density of 1.116 g/mL, should be used to make 4.40 L of an NaOH solution with a pH of 10.5?
3 answers
hgiyug
too confusing