If 15g of NaOh is dissolved in 285 g of water, calculate the following. Assume the density of the solution is 1.06 g/cc.
a) Calculate the moles of NaOH in the solution? My answer is 15gNaOH/40g NaOH= .0375 mole NaOH
b) Waht is the mass % w/w of the solution? My answer is 15g NaOH/ 300g sol NaOH * 100 = 5%
c) What is the molarity of the dolution?
My anser is 0.375 mol NaOH/ 0.283L= 0.13M NaOH
Kindly please correct my answers. Thanks
2 answers
pls can anybody check my answers
a.
I think 15/40 = 0.375 mols. You must have just made a typo because you have 0.375 in part c.
b. good work here. Many students forget to add the 15 and 285 and divide by 285.
c. That looks ok to me.
I think 15/40 = 0.375 mols. You must have just made a typo because you have 0.375 in part c.
b. good work here. Many students forget to add the 15 and 285 and divide by 285.
c. That looks ok to me.