What volume of 0.076M HNO3 is required to titrate 20.0ML of 0.25M Ba(OH)2 solution? use 2 sig figures

Answer 1

Ba(OH)2 + 2HNO3 ==> 2H2O + Ba(NO3)2
mols Ba(OH)2 = M x L = ?
Using the coefficients in the balanced equation convert mols Ba(OH)2 to mols HNO3.
Then M HNO3 = mols HNO3/L HNO3. You have M and mols, solve for L. Convert to mL if desired.