An HNO3 solution has a pH of 3.04. What volume of 0.015 M LiOH will be required to titrate 89.0 mL of the HNO3 solution to reach the equivalence point?

Answer 1

HNO3 + LiOH ==> LiNO3 + H2O

The rxn is 1:1; therefore, we may use
mLHNO3 x MHNO3 = mLLiOH x MLiOH
Convert pH of 3.04 to H^+ by pH = -log(H^+) first, substitute, then solve for mL LiOH.