Calculate the pH of the solution after the addition of the following amounts of 0.0617 M HNO3 to a 70.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04.
1)Volume of HNO3 equal to the equivalence point
2)89.5mL of HNO3
I got pH= 7.37 for 1 but i believe I misinterpreted the question because I thought that volume of HNO3 at 1 is equal to 70. mL
As for #2 i got ph= 3.56
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Nevermind, I figured out what I was doing wrong. Thnx
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