What mass of sulfuric acid, H2SO4, is required to react with 3.27 g of potassium hydroxide, KOH? The products of this reaction are potassium sulfate

Question

and water.

Have both the unbalanced and balanced chemical equations.
Explain how to find the molar mass of the compounds.
Explain how the balanced chemical equation is used to find the ratio of
Explain how many significant figures your answer needs to have.
The numerical answer

Answer 1

unbalanced: ... KOH + H2SO4 --> K2SO4 + H2O
balanced:.......2KOH + H2SO4 --> K2SO4 + 2H2O
Find molar mass by adding the atomic masses of the elements: for example, for H2SO4 that is 2*1 + 1*32 + 4*16 = 96
mols KOH = grams/molar mass KOH = 3.27/56 = 0.583
Convert mols KOH to mols H2SO4 using the coefficients in the balanced equation. 0.583 mols KOH x (1 mol H2SO4/2 mols kOH) = 0.583/2 = ?
Now convert mols H2SO4 to grams H2SO4. g H2SO4 = mols H2SO4 x molar mass H2SO4 = ? g
You may have two significant figures in the final answer using the numbers I've used. If you use 3 figures for the molar mass you may have 3 significant figures in the answer since the initial value is 3.27 g.

Answer 2

FYI, your chemistry teacher knows that you are plagiarizing from here.

-From said chemistry teacher