What mass of sulfuric acid, H2SO4, is required to react with 1.27 g of potassium hydroxide, KOH? The products of this reaction are potassium sulfate

and water.

Have both the unbalanced and balanced chemical equations.
Explain how to find the molar mass of the compounds.
Explain how the balanced chemical equation is used to find the ratio of moles (hint: step 3 in the video).
Explain how many significant figures your answer needs to have.
The numerical answer

1 answer

H2SO4 + 2KOH ==? K2SO4 + 2H2O
mols KOH = grams/molar mass = 1.27/56.1 = 0.0226
Convert mols KOH to mols H2SO4 using the coefficients in the balanced equation. 0.0226 mols KOH x (1 mol H2SO4/2 mol KOH) = 0.0226 x 1/2 = 0.0113.
Then grams H2SO4 = mols H2SO4 x molar mass H2SO4 = ?
There are three significant figures in1.27 so you are allowed 3 in the answer. I don't know about a video.