Given the balanced neutralization equation: H2SO4+2KOH→K2SO4+2H2O

How many moles of potassium hydroxide (KOH) are required to neutralize 4.5 mol of sulfuric acid (H2SO4)? Assume that the sulfuric acid completely dissociates in water.

2 mols of KOH = 1 mol of H2SO2
4.5 mols of H2SO4 = 9 mols of KOH

1 answer

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