M = mol/V
0.442(mol/L)= mol/0.8(L)
MOL = 0.3536 mol
MASS= 0.3536 * Mm MgSO4.7H2O
What mass of MgSO4 · 7H2O is required to prepare 800 mL of a 0.442MMgSO4 solution?
Answer in units of g.
2 answers
Complete and answer the following equation
___Mg(ClO3)2 + ___(NH4)2SO4 ---->
How to balance and figure out what type of chemical reaction.
___Mg(ClO3)2 + ___(NH4)2SO4 ---->
How to balance and figure out what type of chemical reaction.
2 answers