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ALEXELBIANCONERO
Questions (1)
(NH4)2CO3 + NH3+[CO(OH2)6](NO3)2+H2O2
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Answers (2)
M = mol/V 0.442(mol/L)= mol/0.8(L) MOL = 0.3536 mol MASS= 0.3536 * Mm MgSO4.7H2O
MOL FRACTION H2O + MOL FRACTION C12H22O11 = 1 THEN MOL FRACTION H2O = 0.8 MOL FRACTION H2O = MOL H20 / TOTAL MOL MOL H2O = 200/18 = 11.1 THEN 0.8=11.1/(11.1+MOL C12H22O11) MOL C12H22O11 = 0.26MOL MASS OF C12H22O11 = MOL * MOLAR MASS MASS OF C12H22O11
