To use synthetic division to divide \(3x^4 - 5x^3 + 4x^2 - 7x + 1\) by \(x + 1\), we will substitute \(-1\) for \(x\) in synthetic division (since we set \(x + 1 = 0\) giving \(x = -1\)).
Here are the steps:
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Write down the coefficients of the polynomial:
\(3, -5, 4, -7, 1\) -
Set up synthetic division using \(-1\):
-1 | 3 -5 4 -7 1
| -3 8 -12 19
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3 -8 12 -19 20
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Bring down the first coefficient \(3\).
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Multiply \(-1\) by \(3\) and write the result underneath \(-5\): \(-1 \times 3 = -3\).
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Add \(-5\) and \(-3\) to get \(-8\).
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Repeat the process:
- Multiply \(-1\) by \(-8\) to get \(8\), and add to \(4\): \(4 + 8 = 12\).
- Multiply \(-1\) by \(12\) to get \(-12\), and add to \(-7\): \(-7 - 12 = -19\).
- Multiply \(-1\) by \(-19\) to get \(19\), and add to \(1\): \(1 + 19 = 20\).
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The result of the synthetic division is therefore:
- Quotient: \(3x^3 - 8x^2 + 12x - 19\)
- Remainder: \(20\)
So, we can write the result as: \[3x^3 - 8x^2 + 12x - 19 + \frac{20}{x + 1}\]
Thus, the correct response is: 3x^3−8x^2+12x−19+20/(x+1).